Qual o número de moléculas presentes em uma amostra de 8,86g de butanodiona

Qual o número de moléculas presentes em uma amostra de 8,86g de butanodiona



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    2,3 Butanodiona (CH3CO)2
    Massa molar = 86,08 g/ mol

    86,08g de (CH3CO)2 —————> 6,02×10^23 molculas
    8,86 g de ( CH3CO)2 —————> x molculas
    86,08.x =6,02×10^23.8,86
    86,08x=5,33372×10^24
    x=5,33372×10^24/86,08
    x6,20 x10^22 molculas de (CH3CO)2

  • 2,3 Butanodiona (CH3CO)2
    Massa molar = 86,08 g/ mol

    86,08g de (CH3CO)2 —————> 6,02×10^23 molculas
    8,86 g de ( CH3CO)2 —————> x molculas
    86,08.x =6,02×10^23.8,86
    86,08x=5,33372×10^24
    x=5,33372×10^24/86,08
    x6,20 x10^22 molculas de (CH3CO)2


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78 + = 82